Answer
$(-\infty,1]\cup[5,\infty)$
See graph.
Work Step by Step
Step 1. $|x-3|\ge2$ can be separated into $x-3\ge2$ or $x-3\le-2$, thus we have the solution $(-\infty,1]\cup[5,\infty)$
Step 2. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.8 Equations and Inequalities Involving the Absolute Value Function - 2.8 Assess Your Understanding - Page 182: 51
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