Answer
$(-\infty,-1)\cup(1,\infty)$
See graph.
Work Step by Step
Step 1. $|x|\gt1$ can be separated into $x\gt1$ or $x\lt -1$, thus we have the solution $(-\infty,-1)\cup(1,\infty)$
Step 2. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.8 Equations and Inequalities Involving the Absolute Value Function - 2.8 Assess Your Understanding - Page 182: 42
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