Answer
$x=-3$ or $x=3$
Work Step by Step
Using the definition of the absolute value, we have
$$\displaystyle
|x^2-9|=0\\
\Longrightarrow x^2-9=0\\
\Longrightarrow x^2=9 \\
\Longrightarrow x=\pm\sqrt 9\\
\Longrightarrow x=\pm3
$$
Thus, we have:
$x=-3$ or $x=3$