Answer
$(-\infty,-4)\cup(4,\infty)$
See graph.
Work Step by Step
Step 1. $|3x|\gt12$ or $|x|\gt4$ can be separated into $x\lt-4$ or $x\gt4$, thus we have the solution $(-\infty,-4)\cup(4,\infty)$
Step 2. See graph.
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