Answer
$a_2=\dfrac{3}{2} \\ a_3=\dfrac{1}{2} \\ a_4=\dfrac{1}{8} \\ a_5=\dfrac{1}{40} $
Work Step by Step
We are given that $a_n=\dfrac{a_{n-1}}{n}$ and $a_1= 3$. In order to determine the remaining values, we will have to substitute $n=2,3,4,5$ into the given sequence:
$a_2=\dfrac{a_{1}}{2}=\dfrac{3}{2} \\ a_3=\dfrac{a_{2}}{3}=\dfrac{3/2}{2}=\dfrac{1}{2} \\ a_4=\dfrac{a_{3}}{4}=\dfrac{1/2}{4}=\dfrac{1}{8} \\ a_5=\dfrac{a_{4}}{5}=\dfrac{1/8}{5}=\dfrac{1}{40} $
