Answer
$\{a_n\}=n ^{(-1)^{n+1}}$
Work Step by Step
We notice that the sequence always contains a number that starts with $1$ and increases by $1$ each time ($1,2,3,4,5...$). This value is sometimes in the numerator (to the power of $1$) and sometimes in the denominator (to the power of $-1$), depending on whether the term number is even or odd. So, we can determine the pattern as
$$\{a_n\}=n ^{(-1)^{n+1}}$$