Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Chapter 5 Test Prep - Review Exercises - Page 559: 9

Answer

$275^{\circ}6^{\prime}1.8^{ \prime\prime}$

Work Step by Step

We need to solve $275.1005^{\circ}$. Re-write as: $275.1005^{\circ}=275^{\circ}+0.1005^{\circ}$ Since, $1^{\circ}=60^{\prime}$ Thus, $275^{\circ}+0.1005^{\circ}=275^{\circ}+0.1005(60^{\prime})\\=275^{\circ}+6^{\prime}+0.03^{\prime}$ Since, $1^{\prime}=60^{\prime \prime}$ Thus, $275^{\circ}+6^{\prime}+0.03(60^{\prime \prime})=275^{\circ}6^{\prime}1.8^{ \prime\prime}$
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