Answer
$\frac{15}{17}, -\frac{8}{17}, -\frac{15}{8}, -\frac{8}{15}, -\frac{17}{8}, \frac{17}{15}$
Work Step by Step
Given point $(-8,15)$ on the terminal side, we have:
1. $sin\theta=\frac{15}{\sqrt {(-8)^2+(15)^2}}=\frac{15}{17}$
2. $cos\theta=\frac{-8}{\sqrt {(-8)^2+(15)^2}}=-\frac{8}{17}$
3. $tan\theta=\frac{15}{-8}=-\frac{15}{8}$
4. $cot\theta=\frac{1}{tan\theta}=-\frac{8}{15}$
5. $sec\theta=\frac{1}{cos\theta}=-\frac{17}{8}$
6. $csc\theta=\frac{1}{sin\theta}=\frac{17}{15}$
