Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Chapter 5 Test Prep - Review Exercises - Page 559: 11

Answer

$-\frac{\sqrt 3}{2}$, $\frac{1}{2}$, $-\sqrt 3$, $-\frac{\sqrt 3}{3}$, $2$, $-\frac{2\sqrt 3}{3}$

Work Step by Step

Use the figure given in the exercise, we have: 1. $sin\theta=\frac{-\sqrt 3}{\sqrt {(1)^2+(-\sqrt 3)^2}}=-\frac{\sqrt 3}{2}$ 2. $cos\theta=\frac{1}{\sqrt {(1)^2+(-\sqrt 3)^2}}=\frac{1}{2}$ 3. $tan\theta=\frac{-\sqrt 3}{1}=-\sqrt 3$ 4. $cot\theta=\frac{1}{tan\theta}=-\frac{1}{\sqrt 3}=-\frac{\sqrt 3}{3}$ 5. $sec\theta=\frac{1}{cos\theta}=2$ 6. $csc\theta=\frac{1}{sinn\theta}=-\frac{2}{\sqrt 3}=-\frac{2\sqrt 3}{3}$
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