Answer
$47.420^\circ$
Work Step by Step
Given angle $\theta=47^\circ25'11''$, we have $\theta=47^\circ+25'+(\frac{11}{60})'=47^\circ+25.183'=47^\circ+(\frac{25.183}{60})^\circ\approx47.420^\circ$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 5 - Trigonometric Functions - Chapter 5 Test Prep - Review Exercises - Page 559: 8
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