Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Chapter 5 Test Prep - Review Exercises - Page 559: 16

Answer

$-\frac{5\sqrt {26}}{26}, \frac{\sqrt {26}}{26}, -5, -\frac{1}{5}, \sqrt {26}, -\frac{\sqrt {26}}{5}$

Work Step by Step

Given point $(1,-5)$ on the terminal side, we have: 1. $sin\theta=\frac{-5}{\sqrt {(1)^2+(-5)^2}}=-\frac{5}{\sqrt {26}}=-\frac{5\sqrt {26}}{26}$ 2. $cos\theta=\frac{1}{\sqrt {(1)^2+(-5)^2}}=\frac{1}{\sqrt {26}}=\frac{\sqrt {26}}{26}$ 3. $tan\theta=\frac{-5}{1}=-5$ 4. $cot\theta=\frac{1}{tan\theta}=-\frac{1}{5}$ 5. $sec\theta=\frac{1}{cos\theta}=\sqrt {26}$ 6. $csc\theta=\frac{1}{sin\theta}=-\frac{\sqrt {26}}{5}$
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