Answer
$-\frac{4}{5}, \frac{3}{5}, \frac{-4}{3}, -\frac{3}{4}, \frac{5}{3}, -\frac{5}{4}$
Work Step by Step
Given point $(3,-4)$ on the terminal side, we have:
1. $sin\theta=\frac{-4}{\sqrt {(3)^2+(-4)^2}}=-\frac{4}{5}$
2. $cos\theta=\frac{3}{\sqrt {(3)^2+(-4)^2}}=\frac{3}{5}$
3. $tan\theta=\frac{-4}{3}$
4. $cot\theta=\frac{1}{tan\theta}=-\frac{3}{4}$
5. $sec\theta=\frac{1}{cos\theta}=\frac{5}{3}$
6. $csc\theta=\frac{1}{sin\theta}=-\frac{5}{4}$
