Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Test - Page 146: 9

Answer

The required value is $\left( x-3 \right)\left( x-6 \right)$.

Work Step by Step

Consider the expression, ${{x}^{2}}-9x+18$ The given expression can be evaluated as: $\begin{align} & {{x}^{2}}-9x+18={{x}^{2}}-3x-6x+18 \\ & =x\left( x-3 \right)-6\left( x-3 \right) \\ & =\left( x-3 \right)\left( x-6 \right) \end{align}$ Therefore, the value of ${{x}^{2}}-9x+18$ is $\left( x-3 \right)\left( x-6 \right)$.
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