Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Test - Page 146: 23

Answer

The required value is $\left( y-5 \right)\left( {{y}^{2}}+5y+25 \right)$.

Work Step by Step

Consider the expression, ${{y}^{3}}-125$ Evaluate the given expression: ${{y}^{3}}-125={{\left( y \right)}^{3}}-{{\left( 5 \right)}^{3}}$ Use the formula as follows: ${{A}^{3}}-{{B}^{3}}=\left( A-B \right)\left( {{A}^{2}}+AB+{{B}^{2}} \right)$ Then, the expression is: $\begin{align} & {{y}^{3}}-125=\left( y-5 \right)\left( {{\left( y \right)}^{2}}+\left( y \right)\left( 5 \right)+{{\left( 5 \right)}^{2}} \right) \\ & =\left( y-5 \right)\left( {{y}^{2}}+5y+25 \right) \end{align}$ Therefore, the value of ${{y}^{3}}-125$ is $\left( y-5 \right)\left( {{y}^{2}}+5y+25 \right)$.
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