Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Test - Page 146: 22

Answer

The required value is ${{\left( 6x-7 \right)}^{2}}$.

Work Step by Step

Consider the expression, $36{{x}^{2}}-84x+49$ Evaluate the given expression: $36{{x}^{2}}-84x+49={{\left( 6x \right)}^{2}}-2\left( 6x \right)\left( 7 \right)+{{\left( 7 \right)}^{2}}$ Use the formula as follows: ${{A}^{2}}-2AB+{{B}^{2}}={{\left( A-B \right)}^{2}}$ Then, the expression is: $36{{x}^{2}}-84x+49={{\left( 6x-7 \right)}^{2}}$ Therefore, the value of $36{{x}^{2}}-84x+49$ is ${{\left( 6x-7 \right)}^{2}}$.
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