Answer
The value of $x$ is $=26$
Work Step by Step
Consider, $\left| \begin{matrix}
x+3 & -6 \\
x-2 & -4 \\
\end{matrix} \right|=28$
Calculate the above determinant as follows:
$\left| \begin{matrix}
x+3 & -6 \\
x-2 & -4 \\
\end{matrix} \right|=28$
This implies that,
$-4\left( x+3 \right)+6\left( x-2 \right)=28$
Simplify the above equation,
$-4x-12+6x-12=28$
Or,
$2x=52$
Divide by $2$. Now,
$x=26$.
Hence, $x=26$
