Answer
The work done is 1841 foot-pounds.
Work Step by Step
Here, the box is pulled horizontally, such that the angle between the force and direction of motion is $\left( 33{}^\circ -10{}^\circ \right)$.
Now it is known,
$\mathbf{W}=\left\| \mathbf{F} \right\|\left\| \mathbf{AB} \right\|\cos \theta $ …… (1)
As it is given that,
$\left\| \mathbf{F} \right\|=80,\left\| \mathbf{AB} \right\|=25$ and $\theta =\left( 33-10 \right){}^\circ $ …… (2)
Therefore, using (2) in (1)
$\begin{align}
& \mathbf{W}=\left( 80 \right)\left( 25 \right)\cos \left( 33-10 \right){}^\circ \\
& =\left( 2000 \right)\cos \left( 23{}^\circ \right) \\
& =\left( 2000 \right)\left( 0.920 \right) \\
& \approx 1841
\end{align}$
