Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Review Exercises - Page 708: 29

Answer

The expression on the left-side is equal to the expression on the right-side.

Work Step by Step

The given expression on the left side $\cos 4t$ can be written as $\cos 2.2t$. As per the double angle formula, $\cos 2t=1-2{{\sin }^{2}}\theta $. Therefore, using the double angle formula: $\begin{align} & \cos 4t=\cos 2.2t \\ & =1-2{{\sin }^{2}}2t \\ & =1-2{{\left( 2\sin t\cos t \right)}^{2}} \\ & =1-2.4{{\sin }^{2}}t{{\cos }^{2}}t \end{align}$ Now, the expression can be further classified as: $1-2.4{{\sin }^{2}}t{{\cos }^{2}}t=1-8{{\sin }^{2}}t{{\cos }^{2}}t$ Hence, the expression on the left-side is equal to the expression on the right-side.
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