Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Review Exercises - Page 708: 28

Answer

The expression on the left-side is equal to the expression on the right-side.

Work Step by Step

The given expression on the right side $2\sin t\cos t\sec 2t$ can be simplified by applying the double angle formula $\sin 2\theta =2\sin \theta \cos \theta $, reciprocal identity $\sec x=\frac{1}{\cos x}$, and the quotient identity $\tan x=\frac{\sin x}{\cos x}$. Therefore, the expression will be: $\begin{align} & 2\sin t\cos t\sec 2t=\sin 2t.\frac{1}{\cos 2t} \\ & =\frac{\sin 2t}{\cos 2t} \\ & =\tan 2t \end{align}$ Hence, the expression on the left-side is equal to the expression on the right-side.
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