Answer
For the long division problem $3x-5\overset{2x}{\overline{\left){\begin{align}
& 6{{x}^{2}}+8x-4 \\
& \underline{6{{x}^{2}}-10x} \\
\end{align}}\right.}}$
the next step is to subtract $6{{x}^{2}}-10x$ from $6{{x}^{2}}+8x$ to obtain $18x$. Then bring down $-4$ and form the new dividend $18x-4$.
Work Step by Step
Let us consider,
$3x-5\overset{2x}{\overline{\left){\begin{align}
& 6{{x}^{2}}+8x-4 \\
& \underline{6{{x}^{2}}-10x} \\
\end{align}}\right.}}$
And dividend:
$6{{x}^{2}}+8x-4$.
Divisor:
$3x-5$.
We divide:
$3x-5\overset{2x+6}{\overline{\left){\begin{align}
& 6{{x}^{2}}+8x-4 \\
& \underline{6{{x}^{2}}-10x} \\
& \text{ }18x-4 \\
& \text{ }\underline{18x-30} \\
& \text{ }26 \\
\end{align}}\right.}}$
Thus, the next step is to subtract $6{{x}^{2}}-10x$ from $6{{x}^{2}}+8x$ to obtain $18x$. Then bring down $-4$ and form the new dividend $18x-4$.
