Answer
-3,9,-27, 81
Work Step by Step
To find the first four terms of the sequence whose general term is $a_{n}$ = $(-3)^{n}$. We replace n in the formula with 1,2,3, and 4.
n=1, $a_{1}$ = $(-3)^{1}$ = -3
n=2, $a_{2}$ =$(-3)^{2}$ = -3*-3 = 9
n=3, $a_{3}$ = $(-3)^{3}$ = -3*-3*-3 = -27
n=4,$a_{4}$ =$(-3)^{4}$ = -3*-3*-3*-3 = 81
The first four terms are -3,9,-27 and 81.
