Answer
3,12,48, 192
Work Step by Step
To find the first four terms of the sequence whose general term is $a_{n}$ =4$a_{n-1}$, we replace n in the formula with 2,3, and 4.
n=1, $a_{1}$ = 3
n=2, $a_{2}$ =4$a_{2-1}$ = 4$a_{1}$
Substitute $a_{1}$ as 3
$a_{2}$ =4*3 = 12
n=3, $a_{3}$ =4$a_{3-1}$ = 4$a_{2}$
Substitute $a_{2}$ as 12
$a_{3}$ = 4*12= 48
n=4,$a_{4}$ =4$a_{4-1}$= 4$a_{3}$
Substitute $a_{3}$ as 48
$a_{4}$ =4*48 = 192
The first four terms are 3,12,48, 192.
