Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1048: 23

Answer

272

Work Step by Step

$\frac{17!}{15!}$ Try to reduce the fraction before performing the multiplications. We can express 17! as 17! = 17* 16* 15! We can divide both the numerator and the denominator by the common factor, 15!. $\frac{17!}{15!}$ = $\frac{17* 16*15!}{15!}$ = 17*16= 272
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