Answer
$\dfrac{7}{81}$
Work Step by Step
Here, we have $\sum_{i=2}^4(\dfrac{-1}{3})=(\dfrac{-1}{3})^2+(\dfrac{-1}{3})^3+(\dfrac{-1}{3})^4$
$=\dfrac{1}{9}+(\dfrac{-1}{27})+\dfrac{1}{81}$
$=\dfrac{9-3+1}{81}$
$=\dfrac{7}{81}$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1048: 36
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