Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.7 - Combinations of Functions; Composite Functions - Exercise Set - Page 258: 63

Answer

a. $x$ b. $x$ c. $2$ d. $2$

Work Step by Step

Given $f(x)=2x-3$ and $g(x)=\frac{x+3}{2}$, we have: a. $(f\circ g)(x)=2(\frac{x+3}{2})-3=x$ b. $(g\circ f)(x)=\frac{2x-3+3}{2}=x$ c. $(f\circ g)(2)=2$ d. $(g\circ f)(2)=2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.