Answer
a. $x$
b. $x$
c. $2$
d. $2$
Work Step by Step
Given $f(x)=2x-3$ and $g(x)=\frac{x+3}{2}$, we have:
a. $(f\circ g)(x)=2(\frac{x+3}{2})-3=x$
b. $(g\circ f)(x)=\frac{2x-3+3}{2}=x$
c. $(f\circ g)(2)=2$
d. $(g\circ f)(2)=2$