Answer
a. $20x^2-11$
b. $80x^2-120x+43$
c. $69$
d. $123$
Work Step by Step
Given $f(x)=4x-3$ and $g(x)=5x^2-2$, we have:
a. $(f\circ g)(x)=4(5x^2-2)-3=20x^2-11$
b. $(g\circ f)(x)=5(4x-3)^2-2=5(16x^2-24x+9)-2=80x^2-120x+43$
c. $(f\circ g)(2)=20(2)^2-11=69$
d. $(g\circ f)(2)=80(2)^2-120(2)+43=123$
