Answer
a. $14x^2-62$
b. $98x^2+28x-7$
c. $-6$
d. $441$
Work Step by Step
Given $f(x)=7x+1$ and $g(x)=2x^2-9$, we have:
a. $(f\circ g)(x)=7(2x^2-9)+1=14x^2-62$
b. $(g\circ f)(x)=2(7x+1)^2-9=2(49x^2+14x+1)-9=98x^2+28x-7$
c. $(f\circ g)(2)=14(2)^2-62=-6$
d. $(g\circ f)(2)=98(2)^2+28(2)-7=441$
