Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.2 Algebra Techniques for Finding Limits - 14.2 Assess Your Understanding - Page 884: 19

Answer

$-1$

Work Step by Step

Recall: $\lim _{x\rightarrow a}p\left( x\right) =p\left( a\right)$ Thus, $\lim _{x\rightarrow 1}\left( 5x^{4}-3x^{2}+6x-9\right) \\=5\times 1^{4}-3\times 1^{2}+6\times 1-9 \\=5\times 1 -3 \times 1 + 6\times 1 - 9 \\=5-3+6-9 \\=2+6-9 \\=8-9 \\=-1$
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