Answer
$\frac{2-3x}{x^2}$
Work Step by Step
Rewrite the fractions to get a common denominator. $$\frac{2}{x^2}-\frac{3}{x}=\frac{2}{x^2}-\frac{3x}{x^2}$$ Therefore, the expression becomes $\frac{2-3x}{x^2}$.
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