Answer
$$\frac{b-1}{b^2}$$
Work Step by Step
Simplifying using the rules of fractions, we find:
$$\frac{\frac{b^2-1}{b^2}}{b+1} \\ \frac{\left(b+1\right)\left(b-1\right)}{b^2\left(b+1\right)} \\ \frac{b-1}{b^2}$$
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