Answer
$\frac{1}{3}+\frac{1}{\sqrt{x}}$
Work Step by Step
Splitting the fraction into a sum of fractions leaves $$=\frac{\sqrt{x}}{3\sqrt{x}}+\frac{3}{3\sqrt{x}}=\frac{1}{3} \cdot \frac{\sqrt{x}}{\sqrt{x}}+\frac{3}{3} \cdot \frac{1}{\sqrt{x}}=\frac{1}{3}+\frac{1}{\sqrt{x}}$$
