Answer
$$\frac{x^2y}{2x+1}$$
Work Step by Step
Simplifying using the rules of fractions, we find:
$$\frac{\left(\frac{3}{xy}-\frac{5}{x^2y}\right)x^4y^2}{6x^2-7x-5} \\ \frac{x^2y\left(3x-5\right)}{6x^2-7x-5} \\ \frac{x^2y\left(3x-5\right)}{\left(2x+1\right)\left(3x-5\right)} \\ \frac{x^2y}{2x+1}$$
