Answer
$\frac{13}{x^2}+\frac{1}{2x^3}$
Work Step by Step
Splitting the fraction into a sum of fractions leaves $$=\frac{26x}{2x^3}+\frac{1}{2x^3}=\frac{26}{2}\cdot\frac{x}{x^3}+\frac{1}{2x^3}=\frac{13}{x^{3-1}}+\frac{1}{2x^3}=\frac{13}{x^2}+\frac{1}{2x^3}$$
