Answer
$8$
Work Step by Step
Rewrite the fractions to get a common denominator. $$\frac{8y}{y-4}+\frac{32}{4-y}=\frac{8y}{y-4}-\frac{32}{y-4}$$ Since the fractions have the same denominator, they can be added to get $\frac{8y-32}{y-4}=\frac{8(y-4)}{y-4}=8$
