Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5 - Page 401: 91

Answer

x=-2, -4

Work Step by Step

Provided equation is ${{x}^{2}}+6x+8=0$. Consider the quadratic equation of the form \[a{{x}^{2}}+bx+c=0\]. So, the solution of quadratic equation is given by the formula, \[x=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\] Procedure for solving the quadratic equation. Rule 1: Arrange the equation in the decreasing order of power of\[x\] as: ${{x}^{2}}+6x+8=0$ Rule 2: For calculation of solution of the provided equation,use the above-mentioned formula as: For the equation ${{x}^{2}}+6x+8=0$, the value of \[a,b\] and \[c\]is: \[\begin{align} & a=1 \\ & b=6 \\ & c=8 \end{align}\] Now, by application of above formula, the solution is: $\begin{align} & x=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} \\ & =\frac{-6\pm \sqrt{{{6}^{2}}-4\times 1\times 8}}{2\times 1} \\ & =\frac{-6\pm \sqrt{4}}{2} \\ & =-2,-4 \end{align}$ By the use of quadratic equation formula, solution is calculated.
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