Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5 - Page 401: 86

Answer

See Below

Work Step by Step

(a) The quadratic equation is: $p=0.004{{x}^{2}}-0.36x+14$ It is required to calculate percentage of U.S population that was foreign born in 1990. The value of \[x\] is: \[\begin{align} & x=1990-1920 \\ & =70 \end{align}\] Now, the percentage of U.S population can be calculated as: $\begin{align} & p=0.004{{\left( 70 \right)}^{2}}-0.36\left( 70 \right)+14 \\ & =8.4 \end{align}$ According to the graphical data, the percentage of population that was foreign born in 2000 is 10.4. So, the model is overestimate. The difference is: \[8.4-8=0.4\] This overestimates the actual number by 0.4%. The provided model overestimates by 0.4%. (b) Percentage of U.S population is 23%. So, \[p=23\]. Therefore: $\begin{align} & p=0.004{{x}^{2}}-0.36x+14 \\ & 23=0.004{{x}^{2}}-0.36x+14 \\ & 0.004{{x}^{2}}-0.36x-9=0 \end{align}$ Here, quadratic equation with coefficients $a=0.004,b=-0.36\text{ and }c=-9$. So: $\begin{align} & x=\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} \\ & =\frac{-0.36\pm \sqrt{{{0.36}^{2}}-4\left( 0.004 \right)\left( -9 \right)}}{2\left( 0.004 \right)} \\ & \approx -20,110 \end{align}$ Number of years cannot be negative. So, \[x=110\] is considered. Now, the year can be calculated as: \[1920+110=2030\] Hence, the year to reach population to 23 percent is 2030.
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