Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5 - Page 401: 89

Answer

The factors for the equation ${{x}^{2}}-5x+6$is $\left( x-3 \right)\left( x-2 \right)$.

Work Step by Step

The expression is ${{x}^{2}}-5x+6$. Following steps to be followed while method of factorization. Rule1: Arrange the expression in the decreasing order of power of\[x\] as: ${{x}^{2}}-5x+6$ Rule 2: Split the middle term(that is term of\[x\]) as sum or difference of two terms and the product of these two terms is equal to product of constant and the first term (${{x}^{2}}$). ${{x}^{2}}-2x-3x+6$ Rule 3: Taking the x common in first two terms and a constant number common in second two terms as: $x\left( x-2 \right)-3\left( x-2 \right)$ Rule 4: Rearranging the terms as: $\left( x-3 \right)\left( x-2 \right)$ These are the factors for the equation. The factors for the equation ${{x}^{2}}-5x+6$is $\left( x-3 \right)\left( x-2 \right)$.
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