Answer
$\ln2$
Work Step by Step
$avg$ = $\frac{1}{2-1}$$\int_{{\,1}}^{{\,2}}$$\frac{1}{x}$ $dx$
$avg$ = $\ln(x)$ $|_{{\,1}}^{{\,2}}$
$avg$ = $[\ln2-\ln1]$
$avg$ = $\ln2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 7: Transcendental Functions - Section 7.3 - Exponential Functions - Exercises 7.3 - Page 392: 134
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
