Answer
$\pi\ln{16}$
Work Step by Step
$V$ = $\int_{{\,a}}^{{\,b}} A(x)$ $dx$
$V$ = $\int_{{\,\frac{1}{2}}}^{{\,2}}2\pi(x)(\frac{1}{x^{2}})$ $dx$
$V$ = $\int_{{\,\frac{1}{2}}}^{{\,2}}2\pi(\frac{1}{x})$ $dx$
$V$ = $2\pi(\ln{x})$$|_{{\,\frac{1}{2}}}^{{\,2}}$
$V$ = $2\pi(\ln{2}-\ln{\frac{1}{2}})$
$V$ = $4\pi\ln{2}$ = $\pi\ln{16}$