Answer
$4\pi\ln4$
Work Step by Step
$V$ = $\int_{{\,a}}^{{\,b}}{A(y) }$ $dy$
$V$ = $\int_{{\,0}}^{{\,3}}\pi(\frac{2}{\sqrt{y+1}})^{2}$ $dy$
$V$ = $\int_{{\,0}}^{{\,3}}\frac{4\pi}{y+1}$ $dy$
$V$ = $4\pi\ln|y+1|$$|_{{\,0}}^{{\,3}}$
$V$ = $4\pi[\ln4-\ln1]$
$V$ = $4\pi\ln4$
