Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 6: Applications of Definite Integrals - Section 6.6 - Moments and Centers of Mass - Exercises 6.6 - Page 361: 22

Answer

$\overline{x}=\dfrac{a}{2}; \overline{y}=\dfrac{b}{3}$

Work Step by Step

It has been seen that a triangle has vertices $(0,0), (a,0), (\dfrac{a}{2},b)$, whose x-coordinate of the center of mass is $\dfrac{a}{2}$ and which is symmetric about the line $x =\dfrac{a}{2}$ Also, the y-coordinate is a third of the distance of $(\dfrac{a}{2},b)$, which corresponds to $x$-axis. Therefore, the center of mass is: $\overline{x}=\dfrac{a}{2} ;\overline{y}=\dfrac{b}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.