Answer
a)21
b)3500
c)2620
Work Step by Step
a)$\Sigma^7 _{k=1}$3=3(7)=21
b)$\Sigma^{500} _{k=1}$7=7(500)=3500
c)let
$j=k-2$
$k=j+2$
if $k=3 =>j=1$
and
if $ k=264 => j=262$
=a)$\Sigma^{264} _{k=3}$ 10
=a)$\Sigma^{262} _{j=1}$10=10(262)=2620
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 29
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
