Answer
308
Work Step by Step
$7\Sigma _{k=1}$k(2k+1)
=$7\Sigma _{k=1}(2k^2+k)$
=$2\Sigma _{k=1} k^2 +7\Sigma _{k=1}k$
=2$\frac{7(7+1)(2(7)+1}{6}+\frac{7(7+1}{2}$
=308
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 26
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