Answer
7
Work Step by Step
2$\Sigma$k-1 writing this with put sigma notation
2$\Sigma$k-1$\frac{6k}{k+(1)}$ =>$\frac{6(1)}{1+(1)}$ => $\frac{6(2)}{2+(1)}$
=>$\frac{6}{2}$+ $\frac{12}{3}$ =>7
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 1
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