Answer
4$\Sigma_{k=1} k^{2}$=1+4+9+16
Work Step by Step
As
- k=1 (from where Series is starting)
and
- 4 is the Variable On which Operation of $K^{2}$ wll be performed
4$\Sigma_{k=1} k^{2}$=1+4+9+16
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises 5.2 - Page 265: 12
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