Answer
The Derivative is:
$y'=-\csc x\cot x-\frac{2}{\sqrt{x}}$
Work Step by Step
$y=\csc x-4\sqrt{x}+7$
Applying Derivative Rules:
$y'=f'(x)+g'(x)$
$y'=(-\csc x\cot x)-(4)(\frac{1}{2\sqrt{x}})+(0)$
$y'=-\csc x\cot x-\frac{2}{\sqrt{x}}$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 141: 5
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
