Answer
The Derivative is:
$y'=-10-3\sin x$
Work Step by Step
$y=-10x+3\cos x$
Applying Derivative Rules
$y'=(-1)(10)x^{1-1}+(3)(-\sin x)$
$y'=-10-3\sin x$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 141: 1
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