Answer
The Derivative is:
$y'=-\frac{3}{x^2}+5\cos x$
Work Step by Step
$y=\frac{3}{x}+5\sin x$
$y=3x^{-1}+5\sin x$
Applying Derivative Rules:
$y'=f'(x)+g'(x)$
$y'=(-1)(3)x^{-1-1}+(5)(\cos x)$
$y'=-3x^{-2}+5\cos x$
$y'=-\frac{3}{x^2}+5\cos x$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.5 - Derivatives of Trigonometric Functions - Exercises 3.5 - Page 141: 2
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