Answer
$\int^{e^{3}}_{1}$ $\int^{3}_{\ln x}$(x+y) dydx
Work Step by Step
$\int^{3}_{0}$ $\int^{e^{y}}_{1}$ (x+y)dxdy = $\int^{e^{3}}_{1}$ $\int^{3}_{\ln x}$(x+y) dydx
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