Answer
$\dfrac{1}{2}$
Work Step by Step
$\lim\limits_{(x,y) \to (2,-4)} \dfrac{(y+4)}{x(xy-y+4x-4)}=\lim\limits_{(x,y) \to (2,-4)} \dfrac{(y+4)}{x(x-1)(y+4)}=\dfrac{1}{2(2-1)}$
Plug the limits, then we get $\dfrac{1}{2(1)}=\dfrac{1}{2}$
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